>>-.---.--ALPHASTART--"integer"------------>< +-/-+
integer | The number to be used. |
Default: | ALPHASTART"1" |
Phase: | Syntax check |
$SET: | Initial |
With ALPHASTART"1", the COBOL statement:
alphabet myalpha is 66, 67
declares an alphabet consisting of "A" and "B" since, counting from 1, these are the 66th and 67th characters in the ASCII collating sequence. With ALPHASTART"0", MYALPHA consists of "B" and "C".
Comments:
For ANSI conformance use ALPHASTART"1".